\(2^{n+2}-2^n=24\)
\(\Rightarrow2^n\left(4-1\right)=24\)
\(\Rightarrow2^n=8=2^3\)
Vì \(2\ne\pm1;2\ne0\) nên \(n=3\).
Vậy......................
Chúc bạn học tốt!!!
Giải:
\(2^{n+2}-2^n=24\)
\(\Leftrightarrow2^n\left(2^2-1\right)=24\)
\(\Leftrightarrow2^n\left(4-1\right)=24\)
\(\Leftrightarrow2^n.3=24\)
\(\Leftrightarrow2^n=\dfrac{24}{3}=8\)
\(\Leftrightarrow2^n=2^3\)
Vì \(2=2\)
\(\Rightarrow n=3\)
Vậy \(n=3\).
Chúc bạn học tốt!!!
\(2^{n+2}-2^n=24\)
\(\Leftrightarrow2^n\left(2^2-1\right)=24\)
\(\Leftrightarrow2^n.3=24\)
\(\Leftrightarrow2^n=8\)
\(\Leftrightarrow2^n=2^3\)
\(\Leftrightarrow n=3\left(tm\right)\)
Vậy ...
