Question

\(2\left(x+\frac{3}{5}\right)=5-\left(\frac{13}{5}+x\right)\)

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Answer 1

PT <=> \(2x+\frac{6}{5}=5-\frac{13}{5}-x\)

<=> \(\frac{10x+6}{5}=\frac{25}{5}-\frac{13}{5}-\frac{5x}{5}\)

=> 10x + 6 = 25 - 13 - 5x

<=> 10x + 5x = 25 - 13 - 6

<=> 15x = 6

<=> x = 2/5

Vậy S = {2/5}.

Answer 2

\(2\left(x+\frac{3}{5}\right)=5-\left(\frac{13}{5}+x\right)\)

<=> \(2x+\frac{6}{5}=\frac{12}{5}-x\)

<=> \(3x=\frac{6}{5}\) <=> \(x=\frac{2}{5}\)

Answer 3

10x+6=25-13-5x

15x=6

x=2/5

Answer 4

BT<=>2x+6/5=5-13/5-x

<=>10x+6/5=25/5-13/5-5x/5

=>10x+6=25-13-5x

10x+5x=25-13-6

(10+5)x=6

15x=6

x=6:15

x=0,4