Bài 1: Tìm x:
a)\(\frac{3}{4}+\frac{2}{5}x=\frac{29}{60}\)
b)\(1\frac{3}{4}\cdot x+1\frac{1}{2}=-\frac{4}{5}\)
c)\(\frac{11}{12}-\left(\frac{2}{5}+x\right)=\frac{2}{3}\)
d)\(2\frac{3}{4}x=3\frac{1}{7}:0,01\)
e)\(2x\cdot\left(x-\frac{1}{7}\right)=0\)
Tim x, biet:
a/ \(3,8:\left(2.x\right)=\frac{1}{4}:2\frac{2}{3}\)
b/ \(\left(0,25.x\right):3=\frac{5}{6}:0,125\)
c/ \(0,01:2,5=\left(0,75.x\right):0,75\)
d/ \(1\frac{1}{3}:0,8=\frac{2}{3}:\left(0,1.x\right)\)
Tim x
\(\frac{x+2015}{5}+\frac{x+2016}{4}=\frac{x+2017}{3}+\frac{x+2018}{2}\)
2/ tim x
\(\frac{x+2015}{5}+\frac{x+2016}{6}=\frac{x+2017}{7} +\frac{x+2018}{8}\)
3/ tim x
\(\frac{1}{3}+\frac{1}{6}+\frac{99}{101}+\frac{1}{15}+... +\frac{1}{x\left(2x+1\right)}=\frac{1}{10}\)
tim x
a) \(2\frac{1}{2}-x+\frac{4}{5}=\frac{2}{3}-\left(\frac{-4}{7}\right)\)
b) \(\frac{-4}{7}-x=\frac{3}{5}-2x\)
c) \(\frac{9}{2}-\left[\frac{2}{3}-\left(x+\frac{7}{4}\right)\right]=\frac{-5}{4}\)
giúp mình với , mai mình cần rồi
Tìm x
a. \(\sqrt{16x}\)\(+\frac{3}{4}\)\(=2\sqrt{\frac{4}{25}}\)\(+0,01.\sqrt{100}\)
b. \(2\frac{3}{4}x\)\(=3\frac{1}{7}\)\(:0,01\)
c. \(|x|\)\(+3^2\)\(=2^2\)\(+\left(\frac{1}{2}\right)^3\)
Tim so huu ti x
a)\(\frac{2}{3x}-\frac{3}{12}=\frac{4}{5}-\left(\frac{7}{x}-2\right)\))
b)\(\frac{1}{x-1}+\frac{-2}{3}\left(\frac{3}{4}-\frac{6}{5}\right)=\frac{5}{2-2x}\)
c)\(3-\frac{2}{2x-3}=\frac{2}{5}+\frac{2}{9-6x}-\frac{3}{2}\)
e)\(\frac{x}{2}-\frac{1}{x}=\frac{1}{12}\)
BT2: Tim x
\(1.\left(3x+1\right)^2=25\)
\(2.\left[x-\frac{1}{2}\right]+\frac{1}{2}=\frac{5}{8}\)
\(3.\left[x+\frac{3}{4}\right]-\frac{1}{3}=0\)
\(4.\frac{1}{9}.3^4.3x=3^7\)
\(5.\frac{x}{5}=\frac{4}{21}\)
tim x
a)\(2\frac{3}{4}x-1\frac{5}{8}x=1\)
b)\(2\frac{3}{4}x-1\frac{5}{8}x=1\)
c)\(\frac{3}{2}x-\frac{2}{5}=\frac{1}{3}x-\frac{1}{4}\)
d)\(2x-\frac{1}{4}=\frac{5}{6}-\frac{1}{2}x\)
e)\(\frac{-5}{6}+3x=\frac{2}{3}-\frac{1}{2}x\)
f)\(\frac{5}{2}x-\frac{3}{2}=x+\frac{29}{10}\)
g)\(\frac{2}{3}+\frac{7}{3}x=\frac{5}{4}x+\frac{1}{6}\)
h)\(\frac{1}{3}.x+\frac{2}{5}\left(x-1\right)=0\)
giup mk nha moi nguoi
BT1: Tinh
\(\frac{7}{8}.\left(\frac{2}{12}+\frac{4}{10}\right)\)
\(\frac{3}{2}-\frac{5}{6}:\left(\frac{1}{2}\right)^2+\sqrt{4}\)
BT2: Tim x
\(2.x-\frac{5}{4}=\frac{20}{15}\)
\(\left(x+\frac{1}{3}\right)^3=\left(\frac{-1}{8}\right)\)