\(2x+1+4\cdot2^2=6\cdot2^5\)
\(2x+1+4\cdot4=6\cdot32\)
\(2x+1+16=192\)
\(2x+17=192\)
\(2x=192-17\)
\(2x=175\)
\(x=175:2\)
\(x=87,5\)
\(2x+1+4\cdot2^2=6\cdot2^5\)
\(2x+1+4\cdot4=6\cdot32\)
\(2x+1+16=192\)
\(2x+17=192\)
\(2x=192-17\)
\(2x=175\)
\(x=175:2\)
\(x=87,5\)
1 ) Tìm x biết
a) \(x^{10}\cdot\left(x^2\right)^{10}\cdot\left(x^3\right)^{10}\cdot...\cdot\left(x^{10}\right)^{10}\)
b)\(\frac{1}{2}\cdot2^x+4\cdot2^x=9\cdot2^5\)
c)\(3\cdot2^{x+2}=5\cdot2^3\)
\(A=2^0\cdot2^1\cdot2^2\cdot2^3\cdot2^4\cdot...\cdot2^{100}\)
\(B=6^0\cdot6^1\cdot6^2\cdot6^3\cdot6^4\cdot...\cdot6^{600}\)
\(C=7^0\cdot7^1\cdot7^2\cdot7^3\cdot7^4\cdot...\cdot7^{700}\)
\(D=8^1\cdot8^2\cdot8^3\cdot8^4\cdot8^5\cdot...\cdot8^{800}\)
tìm x
1, \(\frac{1}{3}x+\frac{2}{5}\left(x-1\right)=0\)
2, \(\frac{1}{3}+\frac{1}{6}+\frac{1}{10}+...+\frac{2}{x\left(x+1\right)}=\frac{49}{50}\)
3, \(x-\left(\frac{11}{12}-x\right)=x-\frac{3}{4}\)
4, \(-29-4\cdot|3x+6|=-41\)
5, \(\frac{1}{5}\cdot2x+\frac{1}{3}\cdot2^{x+1}=\frac{1}{5}\cdot2^7+\frac{1}{3}\cdot2^8\)
MỌI NGƯỜI LÀM ĐƯỢC CÂU NÀO THÌ LÀM GIÚP EM Ạ
tìm x biết
1)\(-\frac{2}{3}\cdot\left(x-\frac{1}{4}\right)=\frac{1}{3}\cdot\left(2x-1\right)\)
2)\(\frac{1}{5}\cdot2^x+\frac{1}{5}\cdot2^{x+1}=\frac{1}{5}\cdot2^7+\frac{1}{3}\cdot2^8\)
\(^{2\cdot2^2\cdot2^3\cdot.......\cdot2^{10}\cdot5^2\cdot^4\cdot5^6.........\cdot5^{14}}\)có tận cùng bằng bao nhiêu chữ số 0
N=\(\frac{5\cdot\left(2^2\cdot3^2\right)\cdot\left(2^2\right)^6-2\cdot\left(2^2\cdot3\right)^{14}\cdot3^6}{5\cdot2^{28}\cdot3^{19}-7\cdot2^{29}\cdot2^{18}}\)
Tinh N
Tính
\(\frac{5\cdot\left(2^2\cdot3^2\right)^9\cdot\left(2^2\right)^6-2\cdot\left(2^2\cdot3\right)^{14}\cdot3^4}{5\cdot2^{28}\cdot3^{18}+7\cdot2^{29}\cdot3^{18}}\)
a)\(\left(2^2+3\right)\cdot\left(x-5\right)+14=5^2124:2^2\)
b) \(3^2\cdot\left(x+1\right)-3=2^3+7^2\cdot2:14\)
c) \(2^2\cdot3\cdot\left(x+5\right)-6=\left(2^3+2^2\right)\cdot2^2\)
d) \(\left(2^2+1\right)\cdot\left(x+14\right)=5^2\cdot4+\left(2^5+3^2+7^2\right):2\)
e) \(\left(2^2-1\right)\cdot\left(x-1\right)=2^2+\left(6^2+2^6\right):\left(5^2\cdot2\right)\)
g) \(\left(3^2-2\right)\cdot\left(x-12\right)+35=5^2+279:3^2\)
nhìn thì cảm thấy khó nhưng lại rất dễ đó
\(20\%x+\frac{2}{5}x=x-4\)
\(\frac{\frac{2}{3}+\frac{2}{7}\cdot\frac{1}{14}}{-1-\frac{3}{7}+\frac{3}{28}}\)
\(\frac{1\cdot2+2\cdot4+3\cdot6+4\cdot8+5\cdot10}{3\cdot4+6\cdot8+9\cdot12+12\cdot16+15\cdot20}\)
giải hội mik mới cách làm lun nha