\(-2,5+\left|3x+5\right|=-1,25=>\left|3x+5\right|=-1,25-\left(-2,5\right)=-1,25+2,5=1,25\)
\(=>\orbr{\begin{cases}3x+5=1,25\\3x+5=-1,25\end{cases}=>\orbr{\begin{cases}3x=1,25-5=-3,75=>x=-3,75:3=-1,25\\3x=-1,25-5=-6,25=>x=-6,25:3=-2,08\left(3\right)\end{cases}}}\)
Tìm x
\(-2,5+\left|3x+5\right|=-1,25\)
\(d,\left|x-\frac{2}{5}\right|+\frac{1}{2}=\frac{3}{4}\)
e,\(\frac{5}{6}-\left|2-x\right|=\frac{1}{3}\)
g,\(-2,5+\left|3x+5\right|=-1,25\)
\(A=\left(\frac{1,5+1-0,75}{2,5+\frac{5}{3}-1,25}+\frac{0,375-0,3+\frac{3}{11}+\frac{3}{12}}{-0,625+0,5-\frac{5}{11}-\frac{5}{12}}\right):\frac{1890}{2005}+115\)
Tính \(P=2005:\left(\frac{0,375-0,3+\frac{3}{11}+\frac{3}{12}}{-0,625+0,5-\frac{5}{11}-\frac{5}{12}}.\frac{2,5+\frac{5}{3}-1,25}{1,5+1-0,75}\right)\)
Tính:
\(A=\left(\frac{1,5+1-0,75}{2,5+\frac{5}{3}-1,25}+\frac{0,375-0,3+\frac{3}{11}+\frac{3}{12}}{-0,625+0,5-\frac{5}{11}-\frac{5}{12}}\right):\frac{1890}{2005}+115\)
Tìm x trong mỗi tỉ lệ thức sau:
\(\left(2,5-3x\right):\frac{5}{3}=\left(\frac{8}{5}+2x\right):\left(-\frac{8}{17}\right)\)
Tính
\(A=\left(\frac{1,5+1-0,75}{2,5+\frac{5}{3}-1,25}+\frac{0,375-0,3+\frac{3}{11}+\frac{3}{12}}{-0,625+0,5-\frac{5}{11}-\frac{5}{12}}\right)\)
Tìm x trong tỉ lệ thức \(\left(2,5-3x\right):1\frac{2}{3}=\left(\frac{8}{5}+2x\right):\left(-\frac{8}{17}\right)\)
Thực hiện phép tính :
a, \(\sqrt{12\frac{1}{4}}.\left(-\frac{2}{7}\right)^2-\left[2,\left(4\right).2\frac{5}{11}\right]:(-\frac{42}{5})\)
b, \(\left(1-\frac{1}{2}\right).\left(1-\frac{1}{3}\right).\left(1-\frac{1}{4}\right)...\left(1-\frac{1}{2007}\right)\)
c, \(\frac{0,375-0,3+\frac{3}{11}+\frac{3}{12}}{-0,625+0,5-\frac{5}{11}-\frac{5}{12}}+\frac{1,5+1-0,75}{2,5+\frac{5}{3}-1,25}\)
Các bạn giải nhanh giúp mình nha!
