\(\frac{2}{5}+\frac{3}{5}.\left(3x-3\right)=\frac{-5}{10}\)
\(\frac{2}{5}+\frac{3}{5}.3.\left(x-1\right)=\frac{-1}{2}\)
\(\frac{9}{5}.\left(x-1\right)=\frac{-1}{2}-\frac{2}{5}\)
\(\frac{9}{5}.\left(x-1\right)=\frac{-9}{10}\)
\(x-1=\frac{-9}{10}:\frac{9}{5}\)
\(x-1=\frac{-1}{2}\)
\(x=\frac{-1}{2}+1\)
\(x=\frac{1}{2}\)
\(\frac{2}{5}+\frac{3}{5}.\left(3x-3\right)=-\frac{5}{10}\)
\(\frac{3}{5}\left(3x-3\right)=-\frac{5}{10}-\frac{2}{5}\)
\(\frac{3}{5}\left(3x-3\right)=-\frac{9}{10}\)
\(\left(3x-3\right)=-\frac{9}{10}:\frac{3}{5}\)
\(3\left(x-1\right)=-\frac{3}{2}\)
\(x-1=-\frac{1}{2}\)
\(x=\frac{1}{2}\)
Vậy...
2/5+3/5.(3x-3)=(-5/10)
3/5.(3x-3)=(-5/10)-2/5
3/5.(3x-3)=(-9/10)
3x-3=(-9/10):3/5
3x-3=(-3/2)
3x=(-3/2)+3
3x=3/2
x=1/2
