\(-\dfrac{2}{5}+\dfrac{7}{21}\\ =\dfrac{-2\times21+7\times5}{105}=\dfrac{-42+35}{105}=\dfrac{-7}{105}=-\dfrac{1}{15}\)
\(-\dfrac{2}{5}+\dfrac{1}{3}=-\dfrac{6}{15}+\dfrac{5}{15}=-\dfrac{1}{15}\)
\(\dfrac{-2}{5}+\dfrac{7}{21}=\dfrac{-42}{105}+\dfrac{35}{105}=\dfrac{-7}{105}=\dfrac{-1}{15}\)