\(\frac{\left(2.4.2^{16}\right)^2}{11.2^{13}.4^{11}-16^9}\)
\(=\frac{2^2.4^2.\left(2^{16}\right)^2}{11.2^{13}.2^{22}-2^{36}}\)
\(=\frac{2^2.2^4.2^{32}}{11.2^{35}-2^{36}}\)
\(=\frac{2^{38}}{2^{35}.\left(11-2\right)}\)
\(=\frac{2^{35}.2^3}{2^{35}.9}=\frac{2^3}{9}=\frac{8}{9}\)
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