\(\frac{2}{3}\cdot x+\frac{3}{4}=3\)
\(\frac{2}{3}\cdot x=3-\frac{3}{4}\)
\(\frac{2}{3}\cdot x=\frac{12}{4}-\frac{3}{4}\)
\(\frac{2}{3}x=\frac{9}{4}\)
\(x=\frac{9}{4}:\frac{2}{3}\)
\(x=\frac{27}{8}\)
\(\frac{2}{3}\)X+ \(\frac{3}{4}\)= 3.
=> \(\frac{2}{3}\)X= 3- \(\frac{3}{4}\).
=> \(\frac{2}{3}\)X= \(\frac{9}{4}\).
=> X= \(\frac{9}{4}\): \(\frac{2}{3}\).
=> X= \(\frac{27}{8}\).
Vậy X= \(\frac{27}{8}\).
\(\frac{2}{3x}+\frac{3}{4}=3\)
\(\left(=\right)\frac{2}{3x}=\frac{9}{4}\)
\(\left(=\right)2.4=3x.9\)
\(\left(=\right)8=27x\)
\(\left(=\right)x=\frac{8}{27}\)
\(\frac{2}{3}\cdot X+\frac{3}{4}=3\)
\(\frac{2}{3}\cdot x=3-\frac{3}{4}\)
\(\frac{2}{3}\cdot x=\frac{9}{4}\)
\(x=\frac{9}{4}:\frac{2}{3}\)
\(x=\frac{27}{8}\)
\(\frac{2}{3}.x+\frac{3}{4}=3\)
\(\frac{2}{3}.x=3-\frac{3}{4}\)
\(\frac{2}{3}.x=\frac{9}{4}\)
\(x=\frac{9}{4}:\frac{2}{3}\)
\(x=\frac{27}{8}\)
\(\frac{2}{3}.x+\frac{3}{4}=3\)
\(\frac{2}{3}.x=3-\frac{3}{4}\)
\(\frac{2}{3}x=\frac{9}{4}\)
\(x=\frac{9}{4}\div\frac{2}{3}\)
\(x=\frac{27}{8}\)