\(-\frac{2}{3}x+\frac{1}{5}=\frac{1}{3}\times\left(\frac{-1}{6}\right)\)
\(-\frac{2}{3}x+\frac{1}{5}=-\frac{1}{18}\)
\(-\frac{2}{3}x=-\frac{1}{18}-\frac{1}{5}\)
\(\frac{-2}{3}x=\frac{-5}{90}-\frac{18}{90}=-\frac{23}{90}\)
\(x=-\frac{23}{90}:\frac{-2}{3}\)
\(x=-\frac{23}{90}.\frac{3}{-2}=\frac{23}{60}\)
Vậy \(x=\frac{23}{60}\)