\(\frac{2^{30}.\left(3^2\right)^8}{2^{12}.3^{12}.\left(2^3\right)^6}=\frac{2^{30}.3^{16}}{2^{12}.3^{12}.2^{18}}=\frac{2^{30}.3^{16}}{2^{30}.3^{12}}=3^4=81\)
\(\frac{2^{30}.9^8}{6^{12}.8^6}=\frac{2^{30}.\left(3^2\right)^8}{\left(3.2\right)^{12}.\left(2^3\right)^6}=\frac{2^{30}.3^{16}}{3^{12}.2^{12}.2^{18}}=\frac{2^{30}.3^{16}}{3^{12}.2^{30}}=3^4=81\)