Nhận xét \(\left|\frac{2}{3}-\frac{1}{2}+\frac{3}{4}x\right|\ge0;\left|1,5-\frac{11}{17}+\frac{23}{13}y\right|\ge0\Rightarrow\left|\frac{2}{3}-\frac{1}{2}+\frac{3}{4}x\right|+\left|1,5-\frac{11}{17}+\frac{23}{13}y\right|\ge0.\)
Dấu " = " xảy ra \(\Leftrightarrow\hept{\begin{cases}\frac{2}{3}-\frac{1}{2}+\frac{3}{4}x=0\\1,5-\frac{11}{17}+\frac{23}{13}y=0\end{cases}\Leftrightarrow\hept{\begin{cases}\frac{3}{4}x=\frac{2}{3}+\frac{1}{2}\\\frac{23}{13}y=0-1,5+\frac{11}{17}\end{cases}\Leftrightarrow\hept{\begin{cases}\frac{3}{4}x=\frac{-1}{6}\Leftrightarrow x=\frac{-2}{9}\\\frac{23}{13}y=\frac{-29}{34}\Leftrightarrow y=\frac{-377}{782}\end{cases}}}}\)
Vậy x = -2/9; y = -377/782
