2^2x-8 = 16^4 2^2x-8 = (2^4)^4 2^2x-8 = 2^16 => 2x-8 = 16 2x = 16 +8 2x = 24 x = 24 : 2 = 12
2^2x-8 = 16^4 2^2x-8 = (2^4)^4 2^2x-8 = 2^16 => 2x-8 = 16 2x = 16 +8 2x = 24 x = 24 : 2 = 12
tìm x
5)
4x x 5 x 4x 3 5
6)
2
2
x 2 x 1 6
7)
2
3
(3 2) 3 .
4
x x x
8) (3x + 1). (2x- 3) – 6x.(x + 2) = 16
Câu 8. tìm n ∈ R thỏa (-8)3 . 42n= (-2)3n. 164
cac ti le thuc tu cac dang thuc sau
2/5 : 8 va 4/5 :16
4 7/3 : 8 va 3 2/3 : 13
tìm n ∈ R thỏa (-8)3 . 42n= (-2)3n. 164
Tìm n € Z biết:
(-8)3*42n= (-2)3n*164
\(4\frac{25}{16}+25\left(\frac{9}{16}:\frac{125}{164}\right):\left(\frac{_{-27}}{8}\right)\)
Tìm n :
-8^3 * 2^3*n = 4^2*n * 164
Tìm x
22x + 4x + 2 = 272
a,(22x+3)2=121
Tìm x: 3 − 2 2 x − 3 = 2 5 + 2 9 − 6 x − 3 2