Tìm x
\(2^{x-1}+5.2^{x-2}=\frac{7}{32}\)
Tìm x:
\(2^{x-1}+5.2^{x-2}=\frac{7}{32}\)
2x-1+5.2x-2=\(\frac{7}{32}\)
Tìm x:\(2^{x-1}+5.2^{x-2}=\frac{7}{32}\)
\(2^{x-1}\)\(+5.2^{x-2=\frac{7}{32}}\)
tìm x : 2x-1 +5.2x-2=\(\frac{7}{32}\)
Tìm x biết:
2x-1+5.2x-1=\(\frac{7}{32}\)
Tìm x biết:
a. \(2^{x-1}+5.2^{x-2}=\frac{7}{32}\)
b.\(\left|x\left(x^2-\frac{5}{4}\right)\right|=x\)
Số nguyên x thỏa mãn biểu thức: \(2^{x-1}+5.2^{x-2}=\frac{7}{32}\) là x= ......