\(\dfrac{22}{21}\) - \(\dfrac{21}{20}\) + \(\dfrac{1}{20\times21}\)
= \(\dfrac{440}{420}\) - \(\dfrac{441}{420}\) + \(\dfrac{1}{420}\)
= \(\dfrac{440+1-441}{420}\)
= \(\dfrac{0}{420}\)
= 0
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