Question

21¹⁵ và 27⁵ . 49⁸

so sánh júp t k cho

Answer 1

\(21^{15}=3^{15}.7^{15}\)

\(27^5.49^8=\left(3^3\right)^5.\left(7^2\right)^8=3^{15}.7^{16}\)

Vì \(3^{15}.7^{17}< 3^{15}.7^{16}\)Nên \(21^{15}< 27^5.49^8\)

Answer 2

\(21^{15}=\left(3.7\right)^{15}=3^{15}.7^{15}\)

\(27^5.49^8=\left(3^3\right)^5.\left(7^2\right)^8=3^{15}.7^{16}\)

Mà \(3^{15}.7^{15}< 3^{15}.7^{16}\Rightarrow21^{15}< 27^5.49^8\)