=(1/11-1/13)+(1/13-1/15)+(1/15-1/17)+(1/17-1/19)+(1/19-1/21)*462-X=19
=(1/11-1/21)*462-X=19
=10/231*462-X=19
=20-X=19
=X=20-19
=X=1
lop nam cung lam duoc
[2/11.13+2/13.15+2/15.17+2/17.19+2/19.20].462-x=19
( 2/11.13 + 2/13.15 + 2/15.17 + ... + 2/19.21) x 462 - (2104 : ( x + 1,05 ) : 0,1. x = 19
tìm x
a:( 2 + 2 + 2 + 2 + 2 )
_________________________________ .462 _x =19
( 11.13 +13.15 +15.17 +17.19 +19.21)
(\(\frac{2}{11.13}\)+\(\frac{2}{13.15} +\frac{2}{15.17}+...+\frac{2}{19.21}\)).462-[2,04:(x+1,05)]:0,12=19. Tìm x
(2/11.13+2/13.15+.......2/19.21).462-17/x+1,05=19
(2/11.13+2/13.15+....+2/19.21).462-(0,04:(x+1,05)):0,12=19
(2/11.13+2/13.15+.......+2/19.21).462 -{2,04:(x+1,05):0,12=19
Tim x
(2/11.13+2/13.15+...+2/19.21).462-[2,04:(x+1,05)]:0,12=19
[2/11.13+2/13.15+2/15.17+2/17.19+2
