Ta có: 210.615+314.15.413:219 .187.3-315.225
=210.215.315+314.3.5.226:219.97.27.3-315.225
=225.315+315.225.10:225.315.2-315.225
=225.315+5-225.315
=5
Ta có: 210.615+314.15.413:219 .187.3-315.225
=210.215.315+314.3.5.226:219.97.27.3-315.225
=225.315+315.225.10:225.315.2-315.225
=225.315+5-225.315
=5
Rút gọn:
a,\(\frac{15.\left(1352-41\right)}{\left(1352-41\right)\left(150-15\right)}\)
b,\(\frac{2^{10}.6^{15}+3^{14}.15.4^{13}}{2^{18}.18^7.3^3+3^{15}.2^{25}}\)
\(\frac{2^{18}.18^7.3^3+3^{15}.2^{15}}{2^{10}.6^{15}+3^{14}.15.4^{13}}\)= ?
Rút gọn
a) \(\frac{2^{10}.6^{15}+3^{14}.15.4^{13}}{2^{18}.18^7.3^3+3^{15}.2^{25}}\) b) \(\frac{2^{10}.3^{31}+2^{40}.3^6}{2^{11}.3^{31}+2^{41}.3^6}\)
B =7.6^10.2^21.3^6-2^19.6^15
9.6^15.2^13-4.3^15.2^26
thực hiện phép tính; a.\(\frac{2^{18}.18^7.3^3+3^{15}.2^{15}}{2^{10}.6^{15}+3^{14}.15.4^{13}}\)
Tính :
\(\dfrac{2^{18}.18^7.3^3+3^{15}.2^{15}}{2^{10}.6^{15}+3^{14}.15.4^{13}}\)
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a,(100.5^7+5^11:25):(5.5^13:25^2)
b,(3^12+3^11):3^10
c,(2^43+2^4):(2^20+1)
d,(2^22+2^24+2^25):(2^18+2^19+2^20)
e,7.3^9+3^10+51.3^8
rut gon : Q= \(\frac{25.4^{15}.9^9-2^9.6^{20}}{15.2^{25}.3^{19}-11.2^{11}.6^{18}}\)
Câu 1: Chứng tỏ rằng:
\(\frac{1}{20}+\frac{1}{21}+\frac{1}{22}+...+\frac{1}{26}+\frac{1}{27}>\frac{8}{27}\)
Câu 2: Tính:
\(D=\frac{2^{10}.6^{15}+3^{14}.15.4^{13}}{2^{18}.18^7.3^3+3^{15}.2^{25}}\)