\(\left(2x-5\right)^3=8\)
\(\left(2x-5\right)^3=2^3\)
\(2x-5=2\)
\(2x=7\)
\(x=\frac{7}{2}\)
\(b,6⋮x-1\)
\(\Rightarrow x-1\inƯ6\left(\pm1,\pm2,\pm3\right)\)
+ x-1 =1 => x=2
+ x-1 =-1 =>x=0
+ x-1=2 =>x=3
+ x-1=-2 => x= -1
+ x-1 =3 =>x=4
+ x-1=-3 => x=-2
#Giải :
( 2x - 5 )3 = 8
( 2x - 5 )3 = 23
=> 2x - 5 = 2
2x = 7
x = 7/2
6 chia hết cho ( x - 1 )
=> (x - 1) € Ư (6)
Ư (6) = { 1 ; 2 ; 3 ; 6 }
Nếu x - 1 = 1 => x = 2
Nếu x - 1 = 2 => x = 3
Nếu x - 1 = 3 => x = 4
Nếu x - 1 = 6 => x = 7
[ P/S : € - thuộc ]
#By_Ami
a) (2x-5)3=8
(2x-5)3=23
2x-5 =2
2x =2+5
2x =7
x =7/2
b) \(6⋮\left(x-1\right)\)
\(\Rightarrow x-1\inƯ\left(6\right)\)
\(\Rightarrow x-1\in\left\{-1;-2;-3;-6;1;2;3;6\right\}\)
\(\Rightarrow x\in\left\{0;-1;-2;-5;2;3;4;7\right\}\)
Hok tốt nha!!!