`@` `\text {Ans}`
`\downarorw`
`2^x \div 2 = 128?`
`=> 2^x = 128 * 2`
`=> 2^x = 256`
`=> 2^x = 2^8`
`=> x = 8`
Vậy, `x = 8`
______
`4^x \div 4^3 = 16`
`=> 4^x = 16 * 4^3`
`=> 4^x = 4^2 * 4^3`
`=> 4^x = 4^5`
`=> x = 5`
Vậy, ` x = 5`
________
`12^x \div 3 = 48 ?`
`=> 12^x = 48 * 3`
`=> 12^x = 144`
`=> 12^x = 12^2`
`=> x = 2`
Vậy, `x = 2`
________
`3^x - 5 = 81`
`3^x = 81 + 5`
`3^x = 86`
Bạn xem lại đề
`@` `\text {Kaizuu lv uuu}`