\(2^{x+2}-2^x=96\)
\(2^x.\left(2^2-1\right)=96\)
\(2^x.3=96\)
\(2^x=32\)
\(2^x=2^5\)
\(\Rightarrow x=5\)
\(2^{x+2}-2^x=96\)
\(2^x\left(2^2-1\right)=96\)
\(2^x\left(4-1\right)=96\)
\(2^x\cdot3=96\)
\(2^x=96:3\)
\(2^x=32\)
\(2^x=2^5\)
\(x=5\)
\(2^{x+2}-2^x=96\)
\(2^x.\left(2^2-1\right)=96\)
\(2^x.3=96\)
\(2^x=32\)
\(2^x=2^5\)
\(\Rightarrow x=5\)
\(2^{x+2}-2^x=96\)
\(2^x\left(2^2-1\right)=96\)
\(2^x\left(4-1\right)=96\)
\(2^x\cdot3=96\)
\(2^x=96:3\)
\(2^x=32\)
\(2^x=2^5\)
\(x=5\)
1.tim x:
a, 96-3(x+1)=42
b, 5(x+35)=515
c, 12x-33=3 mu 2 nhan 3 mu 3
1) tim x thuoc n biet:
a) 3 mu 4 - x = 81
b) 5 mu x -1 = 125
c) (2 - x) mu 3=27 mu 0
d)3 mu x + 2 -3 mu x +1=182
e) 2 mu x -1 -2 mu x =16
tim x y thuoc z biet x mu 2 cong y nhan x cong y mu 2 bang x mu hai nhan y mu hai
cau1tinh
a) A=4+ 2 mu 2 + 2 mu 3 +... +2 mu 20
b) tim x biet
(x+1) + (x+2) +...+(x+100)=5750
tim x biet
2 mu x x 2 x 3 mu x +1
1.tim x thuoc n biet:
a)3 mu x .3 b)x mu 20 = x c)2 mu x.16 mu 2=1024 d)64.4 mu x=16 mu 8
2.tim n thuoc n sao:
a)3 mu 2.3 mu n=3 mu 5 b)(2 mu 2:4).2mu n=4 c)32<2 mu n<128 d)2.16>_2 mu n>4
ai giai dung va nhanh minh tick cho
tim x thuoc N:
a) 2 mu x =4 nhan 128
b)2 mu x nhan 3 mu x =4 nhan 9
bai 1; cho tong M =126 +213+x. Tim x de M chia het cho 3
bai 2; chung to rang tong ; A= 2 + 2 mu 3 + 2 mu 4 + 2 mu 5 + 2 mu 6 +2 mu 7 +2 mu 9 + 2 mu 10 + 2 mu 12 chia het cho 5
a/[x-2][7-x] > 0 . tim x thuoc Z
b/[x mu 2+13][x mu 2-17] > 0 . tim x thuoc Z
c/[x mu 2-13][x mu 2-17] <0 . tim x thuoc Z
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