`2^3 + 2 . { 12 + 2 . [ 3 xx ( 5 - 2) + 1]} + 1`
`=2^3 + 2 . { 12 + 2 . [ 3 xx 3 + 1]} + 1`
`=2^3 + 2 . { 12 + 2 . [ 9 + 1 ]} + 1`
`=2^3 + 2 . { 12 + 2 . 10 +1}`
`=2^3 + 2 . { 12 + 20 + 1}`
` = 2^3 + 2 . 33`
`=8 + 2 . 33`
`= 8 + 66`
`= 74`
Chúc bạn học tốt !!!
Phần 7) \(5\) : ( \(^{\dfrac{-5}{2}^2}\)) + \(\dfrac{2}{15}.\dfrac{3}{2}\) - ( \(-2018^0\)) = \(5\) : \(\dfrac{25}{4}\) + \(\dfrac{6}{30}\) - \(1\) + \(0,25\)
= \(\dfrac{4}{5}\) + \(\dfrac{1}{5}\) - \(\dfrac{5}{5}\) + \(\dfrac{1}{4}\)
= \(0\) + \(\dfrac{1}{4}\) = \(\dfrac{1}{4}\)
Phần 8) ( \(1,2-\dfrac{1}{2}\) ) : \(1\dfrac{1}{20}\) + \(\dfrac{3}{4}-1,25\) - \(\left(-\dfrac{3}{2}\right)^2\) = \(\dfrac{7}{10}\) \(:\dfrac{21}{20}\) + \(\dfrac{3}{4}\) - \(\dfrac{5}{4}\)
= \(\dfrac{2}{3}\) - \(\dfrac{1}{2}\) = \(\dfrac{4}{6}\) - \(\dfrac{3}{6}\) = \(\dfrac{1}{6}\)
Phần 9) \(\dfrac{\left(-1\right)^6.3^5.4^3}{9^2.2^5}\) = \(\dfrac{1.3^5.2^6}{3^4.2^5}\) = \(3.2=6\)
Phần 10) \(\dfrac{3}{5}+2\dfrac{1}{5}:\left(\dfrac{-1}{2}\right)^3\)- \(1^{2008}\) =
\(\dfrac{3}{5}+\dfrac{7}{5}:\dfrac{-1}{8}-1=\dfrac{3}{5}-\dfrac{56}{5}-\dfrac{5}{5}=\dfrac{3-56-5}{5}=\dfrac{-58}{5}\)
Phần 11) \(12+8.\left(\dfrac{-1}{3}\right)^3+\) \(\left[\left(2018\right)^0:\dfrac{1}{2}\right]^2\) = \(12+8.\dfrac{-1}{27}+2^2\)
= \(12-\dfrac{8}{27}+4=16-\dfrac{8}{27}=\dfrac{424}{27}\)
Phần 12) \(2^3.\left(\dfrac{1}{4}\right)^3-6\dfrac{3}{5}-\dfrac{5}{8}+4\dfrac{3}{5}=8.\dfrac{1}{64}-\dfrac{33}{5}-\dfrac{5}{8}+\dfrac{23}{5}\)
= \(\left(\dfrac{1}{8}-\dfrac{5}{8}\right)-\left(\dfrac{33}{5}-\dfrac{23}{5}\right)\)
= \(\dfrac{-1}{2}-2=\dfrac{-1}{2}-\dfrac{4}{2}=\dfrac{-5}{2}\)
\(CuongDoraemon123\)
