\(2:\left(x-2\right)\Rightarrow x\in BCNN\left(2\right)\Rightarrow B\left(2\right)=2,4\)
Vì 2 chia hết cho (x-n) nên x=3,4
ta co 2 chia het cho[x-2] suy ra x-2 la uoc cua 2
ta co uoc cua 2=1,2
ta co 2 Th
TH1 x-2=1 x=1+2 =3
TH2 x-2=2 x=2+2 =4
Vay x mang nhung gia tri 3,4 neu x thuoc so tu nhien
neu x la so nguyen am thi x-2=[-2],[-1]
ta co
neu x-2 =[-1] thi x=[-1]+2=[-1]
neu x-2 =[-2] thi x=[-2]+2=0
vay x mang nhung gia tri la ;3,4,0,[-1]