\(\left|2-3x\right|-5=-1.\)
\(\Leftrightarrow\left|2-3x\right|=4.\)
\(\Leftrightarrow\left[{}\begin{matrix}2-3x=4.\\2-3x=-4.\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{-2}{3}.\\x=2.\end{matrix}\right.\)
Vậy \(x\in\left\{-\dfrac{2}{3};2\right\}.\)