\(-2+\left(\dfrac{1}{-3}+3\right)\\ =-2+\left(\dfrac{-1}{3}+3\right)\\ =-2+\left(\dfrac{-1+3\times3}{3}\right)\\ =-2+\left(\dfrac{-1+9}{3}\right)\\ =-2+\dfrac{8}{3}\\ =\dfrac{-2\times3+8}{3}\\ =\dfrac{-6+8}{3}\\ =\dfrac{2}{3}\)
\(-2+\left(\dfrac{1}{-3}+3\right)\\ =-2+\dfrac{8}{3}\\ =\dfrac{2}{3}\)
\(-2+\left(\dfrac{1}{-3}+3\right)=-2+\dfrac{8}{3}=\dfrac{2}{3}\)