`2+1/[2+1/[2+1/[2+1/[2+1/2]]]]`
`=2+1/[2+1/[2+1/[2+1/[5/2]]]]`
`=2+1/[2+1/[2+1/[2+2/5]]]`
`=2+1/[2+1/[2+1/[12/5]]]`
`=2+1/[2+1/[2+5/12]]`
`=2+1/[2+1/[29/12]]`
`=2+1/[2+12/29]`
`=2+1/[70/29]`
`=2+29/70=169/70`
`2+1/[2+1/[2+1/[2+1/[2+1/2]]]]`
`=2+1/[2+1/[2+1/[2+1/[5/2]]]]`
`=2+1/[2+1/[2+1/[2+2/5]]]`
`=2+1/[2+1/[2+1/[12/5]]]`
`=2+1/[2+1/[2+5/12]]`
`=2+1/[2+1/[29/12]]`
`=2+1/[2+12/29]`
`=2+1/[70/29]`
`=2+29/70=169/70`
tìm các số tự nhiên x, biết;
30/45 = _______1_________
a+ _____1________
b+ _____1_____
c+ 1/d
Tính nhanh:\(\frac{1^2+1}{2^2+1}+\frac{1^2-1}{2^2-1}-\frac{2^2+1}{3^2+1}+\frac{2^2-1}{3^2-1}+...-\frac{1999^2+1}{2000^2+1}+\frac{1999^2-1}{2000^2-1}\)
nhận xét dùm coi mk làm đúng không nha :
Rút gọn biểu thức A=1+1/2+1/2^2+1/2^3+...+1/2^2012
=> 2A = 1/2^1+1/2^2+...+1/2^2012+1/2^2013
=> 2A - A = 1A =(1/2^1+1/2^2+...+1/2^2012+1/2^2013)-(1/2^0+1/2^1+1/2^2+1/2^3+...+1/2^2012)
=> 1A = 1/2^2012-1/2^0
= 1/2^2012-1/1
mấy bạn coi ntn
Tính:
M=(1-1/2^2).(1-1/3^2).(1-1/4^2)...(1-1/49^2).(1-1/50^2)
N=(3/2-2/2^2).(4/3-2/3^2).(5/4-2/4^2)...(100/99-2/99^2).(101/100-2/100^2)
Điền vào ô vuông các dấu thích hợp (=, <,>)
1^2 ... 1
2^2 ... 1+3
3^2 ...1+3+5
1^3 ... 1^2 - 0^2
2^3 ... 3^2 - 1^2
3^3 ... 6^2 - 3^2
4^3 ... 10^2 - 6^2
(0+1)^2 ... 0^2 + 1^2
(1+2)^2 ... 1^2 + 2^2
(2 + 3)^2 ... 2^3 + 3^2
P=(1+2/1).(1+2/2)+(1+2/3)+....+(1+2/99)
Q=(-1-2-3-4...-99-100).(1/2+2/2^2+1/2^3+...1/2^10)
tính(1+2/1)(1+2/2)(1+2/3).....(1+2/26)(1+2/27)
(1-1/2^2)(1-1/3^2)(1-1/4^2)........(1-1/2007^2)
Gía trị biểu thức 1/2 + 1/2^2 + 1/2^3 +...+ 1/2^10
A. 1/2^10
B. 2^10 -1/2^10
C. (1/2)^1+2+...+10
D. 1
a)1/2+1/2^2+1/2^3+1/2^4+........+1/2^n <1
b)1/2^2+1/3^2+1/4^2+ ... +1/10^2 <1
9.2^x.(2^1005-2^1002+.....+2^3-1)=2^1008-1 *
A=2^1005-2^1002+...+2^3-1 2^3 .
A=2^2.(2^1005-2^1002+......+2^3-1) 8.
A=2^1008-2^1005+.....+2^6-2^3
A=2^1005-2^1002+.....+2^3-1 8.A+A=2^1008-1 9.
A=2^1008-1
Thay 9.a=2^1008-1 vào * ta có: 2^x.(2^1008-1)=2^1008-1
2^x=(2^1008-1):(2^1008-1)
2^x=1
2^x=2^0
x=0
vậy x=0
Lập đề bài cho bài toán này