\(\frac{-x^6}{125}-\frac{y^3}{64}\)
\(=\frac{-\left(x^2\right)^3}{5^3}-\frac{y^3}{4^3}\)
\(=\left(\frac{-x^2}{5}\right)^3-\left(\frac{y}{4}\right)^3\)
\(=\left(\frac{-x^2}{5}-\frac{y}{4}\right)\cdot\left(\frac{x^4}{25}-\frac{x^2y}{20}+\frac{y^2}{16}\right)\)
Tham khảo nhé~
\(-\frac{x^6}{125}-\frac{y^3}{64}\)
\(=-\left(\frac{x^6}{125}+\frac{y^3}{64}\right)\)
\(=-\left(\frac{x^2}{5}+\frac{y}{4}\right)\left(\frac{x^4}{25}-\frac{x^2y}{20}+\frac{y^2}{16}\right)\)
Áp dụng công thức này :
\(a^3-b^3=\left(a-b\right)\left(a^2+ab+b^2\right)\)
Ta có :
\(-\frac{x^6}{125}-\frac{y^3}{64}\)
\(=\left(-\frac{x^2}{5}\right)^3-\left(\frac{y}{4}\right)^3\)
\(=\left(-\frac{x^2}{5}-\frac{y}{4}\right)\left(\frac{-x^4}{25}+-\frac{x^2y}{20}+\frac{y^2}{16}\right)\)
