Question

1.Tinh:

a)\(\frac{2^{12}.5^7+4^6.25^3}{8^5.25^3+\left(2^2.5\right)^6}\)

 

Answer 1

0,5555897934

Answer 2

\(\frac{2^{12}\cdot5^7+4^6\cdot25^3}{8^5\cdot25^3+\left(2^2\cdot5\right)^6}\)

\(=\frac{2^{12}.5^7+2^{12}\cdot5^6}{2^{15}\cdot5^6+2^{12}\cdot5^6}\)

\(=\frac{2^{12}\cdot5^6\cdot\left(1\cdot5+1\right)}{2^{12}\cdot5^6\cdot\left(2^3\cdot1+1\right)}\)

\(=\frac{6}{9}\)

\(=\frac{2}{3}\)

Answer 3

\(\frac{2^{12}.5^7+4^6.25^3}{8^5.25^3+\left(2^2.5\right)^6}=\frac{2^{12}.5^7+\left(2^2\right)^6.\left(5^2\right)^3}{\left(2^3\right)^5.\left(5^2\right)^3+\left(2^2\right)^6.5^6}=\frac{2^{12}.5^7+2^{12}.5^6}{2^{15}.5^6+2^{12}.5^6}\)

                                 \(=\frac{2^{12}.5^6.\left(5+1\right)}{2^{12}.5^6.\left(2^3+1\right)}=\frac{6}{9}=\frac{2}{3}\)