Question

1.tính hợp lý

a)35:\(\left(\frac{-5}{3}\right)+2\frac{1}{2}:\left(\frac{-5}{3}\right)\)

b)10³+2.5³+5³ phần 55

c)27².8⁵ phần 6⁶.32³

mình cần gấp lắm ai giúp mình đi mình tick cho

Answer 1

\(a,35:\left(\frac{-5}{3}\right)+2\frac{1}{2}:\left(-\frac{5}{3}\right)=35.\left(-\frac{3}{5}\right)+\frac{5}{2}.\left(-\frac{3}{5}\right)\)

\(=-21+-\frac{3}{2}\)

\(=\frac{-42-3}{2}=-\frac{45}{2}\)

\(b,\frac{10^3+2.5^3+5^3}{55}=\frac{\left(2.5\right)^3+2.5^3+5^3}{5.11}\)

\(=\frac{5^3\left(2^3+2+1\right)}{5.11}\)

\(=\frac{5^2\left(8+2+1\right)}{11}\)

\(=\frac{5^2.11}{11}=5^2=25\)

\(C,\frac{27^2.2^5}{6^6.32^3}=\frac{\left(3^3\right)^2.2^5}{\left(2.3\right)^6.2^5}\)

\(=\frac{3^6}{2^6.3^6}=\frac{1}{2^6}=\frac{1}{64}\)