Tim x,y thuoc Z biet
a.\(\frac{x+8}{y-7}=\frac{1}{3}\)và x-y=1
b.\(\frac{2x}{x-4y}=\frac{1}{y}\)
Tim x thuoc Z, biet: \(\frac{1}{3}+\frac{1}{6}+\frac{1}{10}+...+\frac{1}{x\left(x+1\right):2}=\frac{2009}{2011}\)
Tim x biet :
a, \(4\frac{1}{3}\left(\frac{1}{6}-\frac{1}{2}\right)\le x\le\frac{2}{3}\left(\frac{1}{2}-\frac{1}{3}-\frac{3}{4}\right)\) x thuoc Z
b , \(|x-3|+1=x\)
1 tim x,y,z biet
\(\frac{-4}{x}=\frac{y}{-14}=\frac{12}{21}=\frac{z}{-63}\)
2 tim n thuoc z n khac 0
a \(\frac{1111100:n}{23331:n}+\frac{-10}{-21}\)
b \(\frac{1075:n}{600:n}=\frac{43}{24}\)
Tim cac so x,y,z,t biet:
\(\frac{27}{4}=\frac{-x}{3}=\frac{3}{y^2}=\frac{\left(z+3\right)^3}{-4}=\frac{\left|t\right|-2}{8}\)
Trinh bai cach lanm ra he
Tim x,y thuoc Z biet \(\frac{5x+7y}{6x+5y}\)\(=1\frac{1}{28}\) va UCLN\(\left(x,y\right)=1\)
tim x thuoc Z biet \(\frac{x}{4}\)= \(\frac{18}{x+1}\)
giup voi
Tim cac so nguyen x,y biet
a)\(\frac{x-3}{y-2}\)=\(\frac{3}{2}\)va x - y = 4
b)\(\frac{x+3}{y-1}\)=\(\frac{3}{4}\)va x + y = 5
tim x,y thuoc z
\(\frac{x}{3}=\frac{6}{y}\)