1/
a, 24 - {12 -[(-10)-(-2)]}
=24-{12-(-8)}
=24-20
=4
b,\(\frac{2}{3}\)+\(\frac{1}{3}\).(\(\frac{-2}{3}\)+\(\frac{5}{6}\)):\(\frac{2}{3}\)
=\(\frac{2}{3}\)+\(\frac{1}{3}\).(\(\frac{-4}{6}\)+\(\frac{5}{6}\)):\(\frac{2}{3}\)
=\(\frac{2}{3}\)+\(\frac{1}{3}\).\(\frac{1}{6}\).\(\frac{3}{2}\)
=\(\frac{2}{3}\)+\(\frac{1}{18}\).\(\frac{3}{2}\)
=\(\frac{2}{3}\)+\(\frac{1}{6}\).\(\frac{1}{2}\)
=\(\frac{2}{3}\)+\(\frac{1}{12}\)
=\(\frac{8}{12}\)+\(\frac{1}{12}\)
=\(\frac{9}{12}\)=\(\frac{3}{4}\)
2/
a,\(\frac{-2}{5}\)+(\(\frac{-5}{9}\)+\(\frac{2}{5}\))
=\(\frac{-2}{5}\)+\(\frac{-5}{9}\)+\(\frac{2}{5}\)
=(\(\frac{-2}{5}\)+\(\frac{2}{5}\))+\(\frac{-5}{9}\)
= 0+\(\frac{-5}{9}\)
= \(\frac{-5}{9}\)
b,\(\frac{17}{13}\)-(\(\frac{4}{13}\)-11)
=\(\frac{17}{13}\)-\(\frac{4}{13}\)+11
=1+11=12
c,\(\frac{3}{5}\).\(\frac{18}{17}\)+\(\frac{3}{5}\).\(\frac{9}{17}\)-\(\frac{3}{5}\).\(\frac{10}{17}\)
=\(\frac{3}{5}\).(\(\frac{18}{17}\)+\(\frac{9}{17}\)-\(\frac{10}{17}\))
=\(\frac{3}{5}\).1=\(\frac{3}{5}\)