Question

1.Phân tích thành nhân tử

a/ -64 + y^2

b/ -27 - x^3

Answer 1

\(a)-64+y^2=\left(y-8\right)\left(y+8\right)\)

\(b)-27-x^3=-\left(27+x^3\right)=-\left(3+x\right)\left(9-3x+x^2\right)\)

Answer 2

- 64 + y ²

= - 8 . 8 + y . y

= ( y + 8 ) . ( y - 8 ) 

-27 - x³

= - ( 27 + x³ )

= - ( 3 + x ) . ( 9 - 3 + x² )