Question

1phân tích thành nhân tử

12x³+4x²-27x-9

gợi ý là phương phát nhóm các hạng tử

 

Answer 1

\(12x^3+4x^2-27x-9=4x^2\left(3x+1\right)-9\left(3x+1\right)\)

\(=\left(4x^2-9\right)\left(3x+1\right)=\left(2x-3\right)\left(2x+3\right)\left(3x+1\right)\)

Answer 2

\(12x^3+4x^2-27x-9\)

\(=4x^2\left(3x+1\right)-9\left(3x+1\right)\)

\(=\left(3x+1\right)\left(4x^2-9\right)\)

Answer 3

\(12x^3+4x^2-27x-9\)

\(=\left(12x^3+4x^2\right)-\left(27x+9\right)\)

\(=4x^2\left(3x+1\right)-9\left(3x+1\right)\)

\(=\left(4x^2-9\right)\left(3x+1\right)\)

\(=\left[\left(2x\right)^2-3^2\right]\left(3x+1\right)\)

\(=\left(2x-3\right)\left(2x+3\right)\left(3x+1\right)\)

Answer 4

\(12x^3+4x^2-27x-9\)

\(=4x^2\left(3x+1\right)-9\left(3x+1\right)\)

\(=\left(3x+1\right)\left(4x^2-9\right)\)

\(=\left(3x+1\right)\left(2x+3\right)\left(2x-3\right)\)