Các câu hỏi tương tự
Cho tỉ lệ thức \(\frac{a}{b}=\frac{c}{d}\)
a,\(\frac{a-b}{a+b}=\frac{c-d}{c+d};\)
b,\(\frac{2a+5b}{3a-4b}=\frac{2c+5d}{3c-4d};\)
c,\(\frac{ab}{cd}=\frac{\left(a-b\right)^2}{\left(c-d\right)^2};\)
Ch\(\frac{a}{b}=\frac{c}{d}\)CMR:
a, \(\frac{2a+5b}{3a-4b}=\frac{2c+5d}{3c-4d}\)
b, \(\frac{ab}{cd}=\frac{\left(a-b\right)^2}{\left(c-d\right)^2}\)
cho \(\frac{a}{b}=\frac{c}{d}\). Chứng minh \(\frac{2a+5b}{3a-4b}=\frac{2c+5d}{3c-4d}\)
cho \(\frac{a}{b}=\frac{c}{d}\)chứng minh rằng \(\frac{2a+5b}{3a-4b}=\frac{2c+5d}{3c-4d}\)
Cho tỉ lệ thức \(\frac{a}{b}=\frac{b}{c}\)CMR : \(\frac{2a^2-3ab+4b^2}{5b^2+6ab}=\frac{2c^2-3cd+4d^2}{5d^2+6cd}\)
cho a/b=c/d.chứng minh rằng: \(\frac{2a+5b}{3a-4b}=\frac{2c+5d}{3c-4d}\)
Cho \(\frac{a}{b}=\frac{c}{d}\)Chứng minh rằng:
a) \(\frac{\left(2a+3b\right)^2}{\left(3a-4b\right)^2}=\frac{\left(2c+3d\right)^2}{\left(3c-4d\right)^2}\)
b) \(\frac{2a^2-3ab+4b^2}{2b^2+5ab}=\frac{2c^2-3cd+4d^2}{2d^2+5cd}\)
Cho tỉ lệ thúc a/bc/d .C/minh rang ta có các tlt saua)frac{3a+5b}{3a-5b}frac{3c+5d}{3c-5d}b)left(frac{a+b}{c+d}right) frac{a^2+b^2}{c^2+d^2}c)frac{a-b}{a+b}frac{c-d}{c+d}d)frac{ab}{cd}left(frac{a-b}{c-d}right)^2
Đọc tiếp
Cho tỉ lệ thúc a/b=c/d .C/minh rang ta có các tlt sau
a)\(\frac{3a+5b}{3a-5b}\)=\(\frac{3c+5d}{3c-5d}\)
b)\(\left(\frac{a+b}{c+d}\right)\) =\(\frac{a^2+b^2}{c^2+d^2}\)
c)\(\frac{a-b}{a+b}\)=\(\frac{c-d}{c+d}\)
d)\(\frac{ab}{cd}\)=\(\left(\frac{a-b}{c-d}\right)^2\)
Cho \(\frac{a}{b}=\frac{c}{d}\). Chứng minh: a, \(\frac{2a+3b}{3a-4b}=\frac{2c+3d}{3c-4d}\)
b, \(\frac{2a^2-3ab+4b^2}{2b^2+5ab}=\frac{2c^2-3cd+4d^2}{2d^2+5cd}\)