Các câu hỏi tương tự
Tính:
\(1\frac{1}{3}.1\frac{1}{8}.1\frac{1}{15}.1\frac{1}{24}.....1\frac{1}{9800}\)
Bài 5:Tính
A=\(1\frac{1}{3}.1\frac{1}{8}.1\frac{1}{15}.1\frac{1}{24}.1\frac{1}{35}\cdot...\cdot1\frac{1}{9800}\)
Mấy số trên là hỗn số đó
Tính :
a) \(S=\frac{1}{5}+\frac{1}{20}+\frac{1}{44}+...+\frac{1}{1175}\)
b)\(S=1\frac{1}{3}.1\frac{1}{8}.1\frac{1}{15}.1\frac{1}{24}.1\frac{1}{35}.....1\frac{1}{9800}\)
a,\(\frac{8}{8}x-\frac{2}{3}=\frac{1}{3}x+1\frac{1}{3}\)
b,\(3\frac{1}{4}.x-1\frac{1}{6}.x-1\frac{2}{3}=\frac{5}{12}\)
Afrac{1}{5cdot8}+frac{1}{8cdot11}+....+frac{1}{xcdotleft(x+3right)}3A3cdotleft(frac{1}{5}-frac{1}{8}right)+left(frac{1}{8}-frac{1}{11}right)+.....left(frac{1}{x}-frac{1}{x+3}right)3A3cdotleft(frac{1}{5}-frac{1}{x+3}right)frac{101}{1540}3Aleft(frac{1}{5}-frac{1}{x+3}right)frac{101}{4620}frac{1}{x+3}frac{1}{5}-frac{101}{4620}frac{1}{x+3}?
Đọc tiếp
A=\(\frac{1}{5\cdot8}+\frac{1}{8\cdot11}+....+\frac{1}{x\cdot\left(x+3\right)}\)
3A=\(3\cdot\left(\frac{1}{5}-\frac{1}{8}\right)+\left(\frac{1}{8}-\frac{1}{11}\right)+.....\left(\frac{1}{x}-\frac{1}{x+3}\right)\)
3A=\(3\cdot\left(\frac{1}{5}-\frac{1}{x+3}\right)=\frac{101}{1540}\)
3A=\(\left(\frac{1}{5}-\frac{1}{x+3}\right)=\frac{101}{4620}\)
\(\frac{1}{x+3}=\frac{1}{5}-\frac{101}{4620}\)
\(\frac{1}{x+3}=?\)
tìm X biết
\(a,\frac{3}{5}-x=0.2;b,\frac{x}{3}-\frac{1}{8}=\frac{5}{8};c,3\frac{1}{3}x-6\frac{3}{4}=3\frac{1}{4}\)
Bài 1 : Tính :
B = \(\frac{\frac{1}{2}+\frac{3}{4}-\frac{5}{6}}{\frac{1}{4}+\frac{3}{8}-\frac{5}{12}}+\frac{\frac{3}{4}+\frac{3}{5}-\frac{3}{8}}{\frac{1}{4}+\frac{1}{5}-\frac{1}{8}}\)
Bài 2 : tìm x và y
a) x3 - 36x = 0
b) \(\frac{x-3}{y-2}=\frac{3}{2}\)và x - y = 4 ( x , y \(\in\)Z )
a) \(5\frac{8}{17}\div x+\frac{-1}{17}\div x+3\frac{1}{17}\div17\frac{1}{3}=\frac{4}{17}\)
b)\(\frac{1}{1\times4}+\frac{1}{4\times7}+\frac{1}{7\times10}+...+\frac{1}{x\times\left(x+3\right)}=\frac{6}{19}\)
Tìm x biết: \(1.\frac{1}{30}:\left(24.\frac{1}{6}-24.\frac{1}{5}\right)-\frac{1.\frac{1}{2}-\frac{3}{4}}{4.x-\frac{1}{2}}=\left(-1.\frac{1}{15}\right):\left(8.\frac{1}{5}-8.\frac{1}{3}\right)\)