Các câu hỏi tương tự
Thực hiện phép tính:\(\left(1-\frac{1}{2018}\right).\left(1-\frac{2}{2018}\right).\left(1-\frac{3}{2018}\right)...\left(1-\frac{2020}{2018}\right)\)
Tính \(B=1+\frac{1}{2}\left(1+2\right)+\frac{1}{3}\left(1+2+3\right)+...+\frac{1}{2018}\left(1+2+3+...+2018\right)\)
Tính:\(\left(2018-\frac{1}{3}-\frac{2}{4}-\frac{3}{5}-...-\frac{2018}{2020}\right):\left(\frac{1}{15}+\frac{1}{20}+\frac{1}{25}+...+\frac{1}{10100}\right)\)
\(A=\)\(\left(1-\frac{1}{2018}\right)\)\(\left(1-\frac{2}{2018}\right)\)\(\left(1-\frac{3}{2018}\right)\)\(...\)\(\left(1-\frac{2020}{2018}\right)\)
P = \(\left(1-\frac{1}{100}\right)\left(\frac{1}{2}-\frac{1}{100}\right)\left(\frac{1}{3}-\frac{1}{100}\right)...\left(\frac{1}{2018}-\frac{1}{100}\right)\)
\(\left(1-\frac{1}{2}\right)\cdot\left(1-\frac{1}{3}\right)\cdot\left(1-\frac{1}{4}\right)\cdot\left(1-\frac{1}{5}\right)\cdot...\cdot\left(1-\frac{1}{2017}\right)\cdot\left(1-\frac{1}{2018}\right)\)
Tính
\(\left(2018-\frac{1}{3}-\frac{2}{4}-\frac{3}{5}-\frac{4}{6}-...-\frac{2018}{2020}\right):\left(\frac{1}{15}+\frac{1}{20}+\frac{1}{25}+\frac{1}{30}+...+\frac{1}{10100}\right)\)
A=\(\left(\frac{1}{2^2}-1\right)\left(\frac{1}{3^2}-1\right)............\left(\frac{1}{2017^2}-1\right)\left(\frac{1}{2018^2}-1\right)\)
B=\(-\frac{1}{2}\)
So sánh A và B
Cho \(A=\left(\frac{1}{2^2}-1\right)\left(\frac{1}{3^2}-1\right)\left(\frac{1}{4^2}-1\right).........\left(\frac{1}{2018^2}-1\right)\)
B= \(-\frac{1}{2}\)
So sánh A và B