\(\frac{1}{1}-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+....+\frac{1}{99}-\frac{1}{100}+\frac{1}{100}-\frac{1}{101}.\)
\(=\frac{1}{1}-\frac{1}{101}\)
\(=\frac{101}{101}-\frac{1}{101}=\frac{100}{101}\)
\(\frac{1}{1}-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+....+\frac{1}{99}-\frac{1}{100}+\frac{1}{100}-\frac{1}{101}.\)
\(=\frac{1}{1}-\frac{1}{101}\)
\(=\frac{101}{101}-\frac{1}{101}=\frac{100}{101}\)
Tính giá trị của biểu thức:
\(\frac{1}{1\times2}+\frac{1}{2\times3}+\frac{1}{3\times4}+...+\frac{1}{98\times99}+\frac{1}{99\times100}\)
Giải giùm nhé! Mình cảm ơn nhìu nhìu! ^__^
\(\frac{1}{1\times2}\)+ \(\frac{1}{2\times3}\)+ \(\frac{1}{3\times4}\)+ ....... + \(\frac{1}{98\times99}\)+ \(\frac{1}{99\times100}\)
đang cần gấp !!!!!!!!
\(\left(\frac{1}{51}+\frac{1}{52}+\frac{1}{53}+...+\frac{1}{100}\right)\div\left(\frac{1}{1\times2}+\frac{1}{3\times4}+\frac{1}{5\times6}+...+\frac{1}{99\times100}\right)\)
tinh gia tri cua bieu thuc \(\frac{1}{1\times2}+\frac{1}{2\times3}+........+\frac{1}{99\times100}\)
tinh gia tri bieu thuc\(\frac{1}{1\times2}+\frac{1}{2\times3}+...+\frac{1}{99\times100}\)
tinh gia tri bieu thuc\(\frac{1}{1\times2}+\frac{1}{2\times3}+...+\frac{1}{99\times100}\)
tinh gia tri bieu thuc a =\(\frac{1}{1\times2+\frac{1}{2\times3+...+\frac{1}{99\times100}}}\)
tinh gia bieu thuc a = \(\frac{1}{1\times2}+\frac{1}{2\times3}+...+\frac{1}{99\times100}\)
Tính giá trị biểu thức: A =\(\frac{1}{1\times2}+\frac{1}{2\times3}+...+\frac{1}{99\times100}\)