\(\left(1\dfrac{2}{9}+\dfrac{11}{6}\right)\times\dfrac{27}{11}-0,5=\left(\dfrac{11}{9}+\dfrac{11}{6}\right)\times\dfrac{27}{11}-\dfrac{1}{2}=\left(\dfrac{66+99}{54}\right)\times\dfrac{27}{11}-\dfrac{1}{2}=\dfrac{165}{54}\times\dfrac{27}{11}-\dfrac{1}{2}=\dfrac{135}{8}-\dfrac{1}{2}=\dfrac{135}{8}-\dfrac{4}{8}=\dfrac{131}{8}\)