1a,\(\frac{8}{5}\)=1\(\frac{3}{5}\)b,\(\frac{9}{2}\)=4\(\frac{1}{2}\)c,\(\frac{7}{4}\)=1\(\frac{3}{4}\)d,\(\frac{10}{3}\)
2a,1\(\frac{3}{4}\)+1\(\frac{5}{8}\)=\(\frac{7}{4}\)+\(\frac{13}{8}\)=\(\frac{14}{8}\)+\(\frac{13}{8}\)=\(\frac{27}{8}\)b,3\(\frac{4}{5}\)x2\(\frac{6}{8}\)=\(\frac{19}{5}\)x\(\frac{22}{8}\)=\(\frac{418}{40}\)=\(\frac{209}{20}\)
3,3\(\frac{2}{5}\)=\(\frac{17}{5}\),3\(\frac{4}{5}\)=\(\frac{19}{5}\) , 8\(\frac{2}{4}\)=\(\frac{34}{4}\),10\(\frac{6}{7}\)=\(\frac{76}{7}\) , 5\(\frac{1}{2}\)=\(\frac{11}{2}\),5\(\frac{3}{4}\)=\(\frac{23}{4}\)
=>\(\frac{17}{5}\)<\(\frac{19}{5}\)=>3\(\frac{2}{5}\)<3\(\frac{4}{5}\) =>\(\frac{34}{4}\)<\(\frac{76}{7}\)=>8\(\frac{2}{4}\)<10\(\frac{6}{7}\) =>\(\frac{11}{2}\)<\(\frac{23}{4}\)=>5\(\frac{1}{2}\)<5\(\frac{3}{4}\)
k mik nha ......