Các câu hỏi tương tự
cho \(G=\left(1+\frac{1}{2}\right)\left(1+\frac{1}{4}\right)...\left(1+\frac{1}{2^{1024}}\right)\)và \(H=\frac{1}{2^{2047}}\). Tính G+H
Cho \(G=\left(1+\frac{1}{2}\right)\left(1+\frac{1}{4}\right)...\left(1+\frac{1}{2^{1024}}\right)\)và \(H=\frac{1}{2^{2047}}\). Tính G+H
Cho \(G=\left(1+\frac{1}{2}\right)\left(1+\frac{1}{4}\right)\left(1+\frac{1}{16}\right)\left(1+\frac{1}{256}\right)...\left(1+\frac{1}{2^{1024}}\right)\)và \(H=\frac{1}{2^{2047}}\)
Tính \(G+H\)
CHO \(G=\left(1+\frac{1}{2}\right)+\left(1+\frac{1}{4}\right)+\left(1+\frac{1}{16}\right)+\left(1+\frac{1}{256}\right)+...+\left(1+\frac{1}{2^{1020}}\right)\)
\(H=\frac{1}{2^{2047}}\) .Tính\(G+H\)
\(\left(1-\frac{1}{2}\right)+\left(1-\frac{1}{4}\right)+\left(1-\frac{1}{8}\right)+....+\left(1-\frac{1}{512}\right)+\left(1-\frac{1}{1024}\right)\)
24 tháng 4 2016 lúc 20:19
Tính :
a) \(\left(1-\frac{1}{3}\right).\left(1-\frac{1}{6}\right).\left(1-\frac{1}{10}\right).\left(1-\frac{1}{15}\right).\left(1-\frac{1}{21}\right)...\left(1-\frac{1}{780}\right)\)
b) \(\left(1-\frac{1}{2}\right)+\left(1-\frac{1}{4}\right)+\left(1-\frac{1}{8}\right)+...+\left(1-\frac{1}{512}\right)+\left(1-\frac{1}{1024}\right)\)
C = \(\left(\frac{1}{2}-1\right)+\left(1-\frac{3}{4}\right)+\left(\frac{7}{8}-1\right)+......+\left(1-\frac{1023}{1024}\right)\) ) . tính c
\(H=\frac{\left(1+97\right)\left(1+\frac{97}{2}\right)\left(1+\frac{97}{3}\right)\left(1+\frac{97}{4}\right)+...+\left(1+\frac{97}{99}\right)}{\left(1+99\right)\left(1+\frac{99}{2}\right)\left(1+\frac{99}{3}\right)\left(1+\frac{99}{4}\right)+...+\left(1+\frac{99}{97}\right)}\)
\(A=\left(1-\frac{1}{2}\right)+\left(1-\frac{1}{4}\right)+\left(1-\frac{1}{8}\right)+...+\left(1-\frac{1}{1024}\right)\)
\(B=4.5^{100}.\left(\frac{1}{5}+\frac{1}{5^2}+\frac{1}{5^3}+...+\frac{1}{5^{100}}\right)+1\)