\(A=\left(\frac{2x-1}{x^2-4}+\frac{x+2}{x^2-x-2}\right):\frac{x-2}{x^2+3x+2}\)
\(=\left[\frac{2x-1}{\left(x-2\right)\left(x+2\right)}+\frac{x+2}{\left(x+1\right)\left(x-2\right)}\right]\cdot\frac{\left(x+1\right)\left(x+2\right)}{x-2}\)
\(=\frac{\left(2x-1\right)\left(x+1\right)+\left(x+2\right)\left(x+2\right)}{\left(x+1\right)\left(x-2\right)\left(x+2\right)}\cdot\frac{\left(x+1\right)\left(x+2\right)}{\left(x-2\right)}\)
\(=\frac{2x^2+2x-x-1+x^2+4x+4}{\left(x-2\right)^2}\)
\(=\frac{3x^2+5x+3}{\left(x-2\right)^2}\)
Liệu có sai đề ?????
tìm gí trị của x để A=11 chứ rút gon thì biết r.