\(\overline{1,ab}=\overline{201,ab}\div126\)
\(\overline{201,ab}\div\overline{1,ab}=126\)
\(201+\overline{0,ab}=126\times1+126\times\overline{0,ab}\)
\(201=126+125\times\overline{0,ab}\)
\(125\times\overline{0,ab}=201-126=75\)
\(\overline{0,ab}=75\div125=0,60\)
Vậy a = 6; b = 0