\(19\frac{1}{4}+\frac{1}{2}.2\frac{1}{3}+5,75-\frac{1}{6}+74\)
=\(\frac{77}{4}+\frac{1}{2}.\frac{7}{3}+\frac{575}{100}-\frac{1}{6}+74\)
= \(\frac{77}{4}+\frac{7}{6}+\frac{23}{4}-\frac{1}{6}+74\)
= \(\left(\frac{77}{4}+\frac{23}{4}\right)+\left(\frac{7}{6}-\frac{1}{6}\right)+74\)
= \(\frac{100}{4}+1+74\)
= 100
^^
\(19\frac{1}{4}+\frac{1}{2}\cdot2\frac{1}{3}+5,76-\frac{1}{6}+74=\frac{1001}{100}=100,01\)