\(\left(1999.1998+1998+1997\right).\left(1+\frac{1}{2}:1\frac{1}{2}-1\frac{1}{3}\right)\)
\(=\left(1999.1998+1998+1997\right).\left(1+\frac{1}{2}:\frac{3}{2}-\frac{4}{3}\right)\)
\(=\left(1999.1998+1998+1997\right).\left(1+\frac{1}{3}-\frac{4}{3}\right)\)
\(=\left(1999.1998+1998+1997\right).\left(\frac{4}{3}-\frac{4}{3}\right)\)
\(=\left(1999.1998+1998+1997\right).0=0.\)
< 1999 x 1998 + 1998 + 1997 > x < 1 1/2 : 1 1/2 - 1 1/3 >
tính
(1/2+1/3+1/4+...+1/2000)/(1999/1+1998/2+1997/3+...1/1999)
Tính các tổng sau:
1,S1=1+(-3)+5+(-7)+...+1997+(-1999)
2,S2=1+(-2)+(-3)+4+5+(-6)+(-7)+8+...+1997+(-1998)+(-1999)+2000
3,S3= 2-4+6-8+...+1998-2000
4,S4=2-4-6+8+10-12-14+16+...+1994-1996-1998+2000+2009
Các bạn ơi giúp mình với ạ,mình đang cần gấp !!!!
CMR:
1) 19971999 - 19971998 chia hết cho 4
2) 19971998 - 19981999 chia hết cho 4
a) A= 79/1999 + 191/1998 + 947/1997 + 673/1998 + 110/1999.
Hãy so sánh A với 1
b) tính:
M= 1 + 1/2 + 1/2^2 + .......+ 1/2^99 + 1/2^100 + 1/2^100.
Tìm x, biết:
\(\left(\frac{1999}{2}+\frac{1998}{3}+\frac{1997}{4}+.......+\frac{1}{2000}+4000\right)x=1+\frac{1}{2}+\frac{1}{3}\)\(\frac{1}{3}\)
\(\frac{\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+...+\frac{1}{20}}{\frac{1999}{1}+\frac{1998}{2}+\frac{1997}{3}+...+\frac{1}{1999}}\)
\(E=\frac{\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+...+\frac{1}{2000}}{\frac{1999}{1}+\frac{1998}{2}+\frac{1997}{3}+..+\frac{1}{1999}}\)
Tinh gia tri moi biêu thuc sau:a.0,1+0,2+0,3+...+0,9+0,10+0,11+...+0,19. B. (1999×1998+1998×1997)×(1+1/2:1 1/2_1 1/3)
