Question

(1/7+x)^3=(2x+3)^3

Answer 1

\(\left(\frac{1}{7}+x\right)^3=\left(2x+3\right)^3\)

\(\Rightarrow\frac{1}{7}+x=2x+3\)

\(\Rightarrow2x-x=\frac{1}{7}-3\)

\(\Rightarrow x=-\frac{20}{7}\)

Answer 2

\(\left(\frac{1}{7}+x\right)^3=\left(2x+3\right)^3\)

\(\Rightarrow\frac{1}{7}+x=2x+3\)

\(\Rightarrow2x-x=\frac{1}{7}-3\)

\(\Rightarrow x=-\frac{20}{7}\)

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