\(-\dfrac{16}{x+2}=\dfrac{x+2}{-4}\\ \Leftrightarrow\left(x+2\right)^2=\left(-16\right)\cdot\left(-4\right)\\ \Leftrightarrow\left(x+2\right)^2=64\\ \Leftrightarrow\left[{}\begin{matrix}x+2=8\\x+2=-8\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=6\\x=-10\end{matrix}\right.\)
- 16/x + 2 = x + 2/-4
=> (x + 2)2 = (- 16) . (- 4)
=> (x + 2)2 = 64
vậy x + 2 = 8 <=> x = 6
x + 2 = - 8 <=> x = - 10
x = [6 ; - 10]
⇔(x+2)\(^2\)=(−16)⋅(−4)
⇔(x+2)\(^2\)=64
\(\left\{{}\begin{matrix}x +2=8\\x+2=-8\end{matrix}\right.\)
\(\left\{{}\begin{matrix}x=6\\x=-10\end{matrix}\right.\)
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