\(\frac{1}{6}-\left|x-2\right|=-\frac{5}{6}\)
\(\Rightarrow x-2=\frac{1}{6}-\left(-\frac{5}{6}\right)\)
\(\Rightarrow\left|x\right|=\orbr{\begin{cases}3\\-3\end{cases}}\)
\(\Rightarrow x=3\)
\(\frac{1}{6}\)-/x-2/ = -\(\frac{5}{6}\)<=> /x-2/ = \(\frac{1}{6}\)+ \(\frac{5}{6}\)
<=> /x-2/=1
<=>\(\orbr{\begin{cases}x-2=1\\x-2=-1\end{cases}}\)<=> \(\orbr{\begin{cases}x=3\\x=1\end{cases}}\)
Vậy x=3 hoặc x=1