5=1001−𝑥+1001
5=2002−𝑥
5=−𝑥+2002
5−2002=−𝑥+2002−2002
−1997=−𝑥
𝑥=1997
\(-16+8+13=1001-x+1001\)
⇔\(5=2002-x\)
⇔\(x=1997\)
\(\text{- 16 + 8 + 13 = 1001 - x + 1001}\\ 5=1001-x+1001\\ 5=2002-x\\ 2002-x=5\\ x=2002-5\\ x=1997\)
5=1001−𝑥+1001
5=2002−𝑥
5=−𝑥+2002
5−2002=−𝑥+2002−2002
−1997=−𝑥
𝑥=1997
\(-16+8+13=1001-x+1001\)
⇔\(5=2002-x\)
⇔\(x=1997\)
\(\text{- 16 + 8 + 13 = 1001 - x + 1001}\\ 5=1001-x+1001\\ 5=2002-x\\ 2002-x=5\\ x=2002-5\\ x=1997\)
Bài 2. Tìm số nguyên x , biết:
a) −16−(−8−13)=1001−(x−1001) b) x−15−[(27+x)−(x−13)]=−1
3+3/7-3/11+3/1001-3/13/9/1001-9/13+9/7-9/11+9
1,Tính
[(24*47-23) / (24+47+23)] * [(3+3/7-3/11+3/1001-3/13) / (9/1001-9/13+9/7-9/11+9)]
Tính nhanh:
A=24.47-23/24+47-23 . (3+3/7-3/11+3/1001-3/13)/(9/1001-9/13+9/7-9/11+9)
tính nhanh:
\(\dfrac{24.47-23}{24+47.23}.\dfrac{3+\dfrac{3}{7}-\dfrac{3}{11}+\dfrac{3}{1001}-\dfrac{3}{13}}{\dfrac{9}{1001}-\dfrac{9}{13}+\dfrac{9}{7}-\dfrac{9}{11}+9}\)
Tinh
a} A=24x47-23\24+47- 23 x 3+3\7-3\11=3\1001-3\13 \ 9\1001-9\13+9\7-9\11+9
b} M=1+2 +2 mũ 2 +2mu3+....+2mu2012\2mu2014-2
tính giá trị biểu thức:
A= 24 . 47 - 23 / 24 + 47 - 23 . (3 + 3 + 3/7 - 3 /11 +3 / 1001 - 3/13) / ( 9/ 1001 - 9 /13 +9/7 - 9/ 11 +9 )
1+(-6)+11+(-16)+......+(-996)+1001
1+(-2)+(-3)+4+5+(-6)+(-7)+8+....+2001+(-2002)+(2003)+2004+2005
A=\(\frac{24.47-23}{24+47-23}.\frac{3+\frac{3}{7}-\frac{3}{11}+\frac{3}{1001}-\frac{3}{13}}{\frac{9}{1001}-\frac{9}{13}+\frac{9}{7}-\frac{9}{11}+9}\)
Hỏi A=?