\(16\cdot4^{x+1}=64\)
\(\Leftrightarrow4^{x+1}=4\)
\(\Leftrightarrow x+1=1\)
\(\Leftrightarrow x=0\)
Ta có: 16 x \(4^{x+1}\)=64
Nên \(4^{x+1}\) =64 : 16 = 4=4\(4^1\)
Suy ra x+1 =1 =>x = 0
hc tot nha
\(16.4^{x+1}=64\)
\(\Rightarrow4^{x+1}=64:16\Rightarrow4^{x+1}=4\)
\(\Rightarrow x+1=1\Rightarrow x=0\)
16 . 4x+1 = 64
4x+1 = 64 : 16
4x+1 = 4
Vì 4 = 41 nên 4x+1 = 40+1 = 41
16 x 4x+1 = 64
<=> 42 x 4x+1 = 43
<=> 4x+1 = 43 : 42
<=> 4x+1 = 41
<=> x + 1 = 1
<=> x = 0
Vậy x = 0
~ Hok tốt ~
