Question

1/5x8±1/8x11±1/11x14±...±1/x(x±3)=27/480

 

Answer 1

\(\frac{1}{5.8}+\frac{1}{8.11}+\frac{1}{11.14}+...+\frac{1}{x\left(x+3\right)}=\frac{27}{480}\)

\(\Rightarrow\frac{1}{3}\left(\frac{1}{5}-\frac{1}{8}+\frac{1}{8}-\frac{1}{11}+...+\frac{1}{x}-\frac{1}{x+3}\right)=\frac{27}{480}.\frac{1}{3}\)

\(\Rightarrow\frac{1}{3}\left(\frac{1}{5}-\frac{1}{x+3}\right)=\frac{3}{160}\)

\(\Rightarrow\frac{1}{5}-\frac{1}{x+3}=\frac{1}{160}\)

\(\Rightarrow\frac{1}{x+3}=\frac{31}{160}\)

\(\Rightarrow160=31x+93\)

\(\Rightarrow31x=67\)

\(\Rightarrow x=\frac{67}{31}\)